14) A kitchen using a 120V outlet is protected by a 20A fuse. How many 850W toasters could be plugged in at the same time without blowing a fuse? a) 1 b) 2 c) 3 d) 142

Answer 1

This uses one of the fundamental equations in circuit analysis, P (power) = I (current) * V (voltage)

The permissible power through the outlet would be P_allow = 120V * 20A = 2400 W.

How many 850 toasters can be loaded on the circuit? P_allow / P_toaster = 2400 W / 850 W = 2.8 toasters.

I would presume that we are not considering fractional toasters, so we have to round down, so the answer should be 2 toasters.