
Mark M. answered 04/16/21
Mathematics Teacher - NCLB Highly Qualified
z1 = √3 + i
r1 = 2
arctan 1/√3 = π/6
θ1= π/6
z2 = 1 + i
r2 = √2
arctan 1 = π/2
θ2 = π/2
(z1)(z2) = (r1)(r2)[cos (θ1 + θ2) + i sin (θ1 + θ2)]
Can you substitute values and answer?
Bai W.
2[cos(2pi/3)+i sin(2pi/3)] ?04/23/21