Raymond B. answered 04/15/21
Tutor
5
(2)
Math, microeconomics or criminal justice
3004
3040
3044
3400
3440
3404
3444 7 numbers for the 3000's
make it 8(7)+1= 57 for 4000's with 4000 the extra one
5, 6, & 7 thousands, 3x7 = 21
21+7+57 = 85 numbers with at least one four digit between 3000 and 7999