2. A 0.650-kg mass is attached to a spring of spring constant 13.0 N/m along a horizontal frictionless surface. The object oscillates in simple harmonic motion and has an amplitude of 13.0 cm.

Question

a. What is the maximum speed of the mass?

b. What is the total energy of the system?

c. What is the speed of the object at a displacement of 6.5 cm?

Answer 1

Vmax = Amp*w = A (K/m)^1/2

= 13*10^-2 ( 13/0.65) ^1/2

Total Energy = 1/2 ( K A² ) = 1/2 *13 *( 13*10 ^-2 ) ² J

v² = w² A² - w² X²

Now plug in all values to get V at X= 6.5 *10^-2 in m/s