sin(A+B) = sinAcosB + sinBcosA = 3/5·(-7/25) + (4/5)(24/25) = 3/5
Heather B.
asked 04/14/21You are given that cos(A)=4/5, with A in Quadrant I, and sin(B)=24/25, with B in Quadrant I. Find sin(A+B). Give your answer as a fraction.
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