Shiky T.

asked • 04/13/21

What are the consequences of this new modification of the round-robin scheuling?

In a round-robin scheduler, usually a ready queue contains all processes waiting for CPU burst time. Each process exists exactly once in the queue. Suppose that the scheduler allowed a process to exist more than once in the queue.

  1. What are the consequences of this new modification of the round-robin scheuling?
  2. When this new scheduling modification can be useful?


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