If cos of theta = -6/7 and sin of theta < 0 . Find the exact values of each of the trigonometric functions of theta.

Answer 1

Theta is in quadrant III

cos(theta) = -6/7, sin(theta)<0

hypotenuse^2 = 7^2 =49, opposite side =-sqr(49-36) =-sqr13

sin(theta) =-sqr13/7

csc(theta) =-7/sqr13

sec(theta) =-7/6

tan(theta)=sqr13/6

cot(theta) = 6/sqr13