
Sidney P. answered 04/07/21
Minored in physics in college, 2 years of recent teaching experience
a) Distance = PQ + QR + RS + SQ + QS = 3 + 5 + 7 + 12 + 12 = 39 km.
b) Displacement = final minus initial positions = S - P = 15 km.
ARIANNE B.
asked 04/06/21I. A car moving along in a straight highway from point P to point Q to point R and to point S, then back to point Q and finally to point S as shown in the figure below.
a) Find the distance travelled by car.
b) Find the displacement of the car.
DETAILS:
DISTANCES OF THE FOLLOWING POINTS:
P TO Q=3KM
Q TO R=5KM
R TO S=7KM
Sidney P. answered 04/07/21
Minored in physics in college, 2 years of recent teaching experience
a) Distance = PQ + QR + RS + SQ + QS = 3 + 5 + 7 + 12 + 12 = 39 km.
b) Displacement = final minus initial positions = S - P = 15 km.
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