Yefim S. answered • 04/05/21
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xC = (m1x1 + m2x2)/(m1 + m2) = (2kg·0m + 8kg·5m)/(2kg + 8kg) = 4 m
Bella L.
asked • 04/05/21Where is the center of mass of these particles?
Two particles are connected by a massless rod. The 2.0 kg mass is positioned at x = 0, and the 8.0 kg mass is positioned at x = 5m.
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Dr Gulshan S. answered • 04/05/21
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