
Yefim S. answered 04/02/21
Math Tutor with Experience
v0x = 2.98m/1.1s = 2.71 m/s
y = v0yt - gt2/2 or 0.67 = 1.1v0y - 9.8·1.12/2; 1.1v0y = 0.67 + 5.929; v0y = 6.0 m/s
v0 = (2.712 + 6.02)1/2 = 6.58 m/s
Nazar Y.
asked 04/02/21This is a projectile motion question. I'm given the following context:
Height: 0.67 m
Distance: 2.98 m
Time: 1.1 s
Gravitational Acceleration: 9.8 m/s^2
How can I find the initial velocity?
Yefim S. answered 04/02/21
Math Tutor with Experience
v0x = 2.98m/1.1s = 2.71 m/s
y = v0yt - gt2/2 or 0.67 = 1.1v0y - 9.8·1.12/2; 1.1v0y = 0.67 + 5.929; v0y = 6.0 m/s
v0 = (2.712 + 6.02)1/2 = 6.58 m/s
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