Solve the equation sin2θ-cosθ=0 on the interval 0 ≤ θ ≤ 2pi. Answers must be exact values in radians (NOT decimals).

Answer 1

2sinθcosθ - cosθ = 0;

cosθ(2sinθ - 1) = 0

cosθ = 1; θ = 0 or θ = 2π; sinθ = 1/2 θ = π/6 or θ = 5π/6

Answer 2