Let R=the length of the fence by the road and F the length of the other side (the field)
8R + 6(R+2F) = 1600
14R + 12F = 1600
7R + 6F = 800
F = (800-7R)/6
Area = RF = (800R-7R2)/6
At maximum 14R = 800 and 12F=800.
I am always uneasy when these problems don't work out with nice answers, but I think this is correct.