Mike D. answered • 03/28/21

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This is a conservation of mechanical energy question

Suppose the minimum velocity is v

Then mechanical energy at top of 15m hill is 0.5 m v^{2} + mgh = 0.5 mv^{2} + 15mg

g = 9.81 m/s/s (acceleration due to gravity).

All of this (assuming no loss due to friction) is converted to potential energy at top of 29m hill

So 0.5 m v^{2} + 15mg = 29mg

You can solve this for v