Mark M. answered 03/26/21
Retired math prof. Calc 1, 2 and AP Calculus tutoring experience.
Draw a diagram.
The upper right corner has coordinates (x, 1-x2) and the upper left corner has coordinates (-x, 1-x2). The height of the rectangle is 1-x2 and the width is 2x.
Let A(x) = area of rectangle = 2x(1 - x2) = -2x3 + 2x
A'(x) = -6x2 + 2 = 0 when x = 1/√3
Area is maximized when width = 2x = 2/√3 and height = 1 - x2 = 2/3