sinθ = cos(90° - θ) and cosθ = sin(90° - θ)
So, sin72° = cos18° and cos43° = sin47°
Eva M.
asked 03/26/211.) sin(72) = cos( )
2.). cos(43) = sin ( )
sinθ = cos(90° - θ) and cosθ = sin(90° - θ)
So, sin72° = cos18° and cos43° = sin47°
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