A pipe of constant radius carries water at 3.25 m/s. The pipe starts at ground level, then rises to 5.00 m high, where it pours into the air at 1.00 atm. What is the water pressure at ground level?

Answer 1

Hello Tamia,

Using Bernoulli' s Theorem

P/d +1/2 V² + gh = Constant

P1/d +1/2 V1 ² + gh1 = P2 /d +1/2 V2² + gh2

d = density of air = 1.22 kg/m3

AV = Constant ( Equation of Continuity)

pi r1² V1 = pi r2 ² V2

r1 V1² = r2 V2 ² So V 1 = V2

P1 = ? , d = 1.22, V2 = V1 = 3.25 m/s ,P2 = 1 at = 1.01 * 10 ⁵ Pa, h1 =0 , h2 = 5m

Calculate P1 by plugging in all values

Get back if you have some question

(You may change back to at. as pressure unit )

P1 =P 2 + d*g*h2 ( in short)