Find the exact value of the trigonometric expression when sin(u) = 5/13 and cos(v) = − 15/17 . (Both u and v are in Quadrant II.)

Question

If you could please walk me through the process

Answer 1

sin(u)**2 + cos(u)**2 = 1

(5/13)**2 + cos(u)**2 = 1

cos(u)**2 = 144/169

cos(u) = -12/13 since in QII

tan(u) = sin(u)/cos(u)

cot(u) = 1/tan(u)

sec(u) = 1/cos(u)

csc(u) = 1/sin(u)

sin(v)**2 + cos(v)**2 = 1

sin(v)**2 + (-15./7)**2 = 1

sin(v)**2 = 64/289

sin(v) = 8/17 since in QII

tan(v) = sin(v)/cos(v)

cot(v) = 1/tan(v)

sec(v) = 1/cos(v)

csc(v) = 1/sin(v)