cosθ−2sinθcosθ=0

Question

I have to solve the trigonometric equation but I'm kinda confused on how I should begin

Answer 1

first, factor the equation

cos(x) -2sin(x)cos(x)=0

cos(x)(1-2sin(x))=0

second, let the 2 expressions equal 0

cos(x)=0, 1-2sin(x)=0

third, solve each equation separately.

cos(x)=0: x=pi/2, (3*pi)/2, (5*pi)/2, .. ((2n+1)*pi)/2, 0<=n

1-2sin(x)=0,

1=2sin(x)

1/2=sin(x), x=pi/2, (5*pi)/2, (9*pi)/2, ((4n+1)*pi)/2, 0<=n

Answer 2

Factor out the common factor:

cos θ - 2 sin θ cos θ = 0

cos θ (1 - 2 cos θ) = 0

Can you now solve for θ and answer?