Tom K. answered 03/18/21
Knowledgeable and Friendly Math and Statistics Tutor
This is a simple problem. r dr dθ = dxdy. Thus, using I[a, b] for the integral from a to b and E[a,b] for the evaluation from a to b, we have
I[0, 2π][0,4+4sinθ] r dr dθ = I[0, 2π] 1/2r2 E[0,4 + 4sinθ] dθ =
I[0, 2π] 16 + 32sinθ + 16sin2θ dθ substituting sin2θ = 1/2 - 1/2cos2θ, 16sin2θ = 8 - 8 cos2θ
I[0, 2π] 24 + 32sinθ - 8cos 2θ dθ =
24θ - 32cosθ - 4sin2θ e[0, 2π] = 24*2π = 48π