a .08kg bullet travelling at 713m/s strikes a 2.4kg block of wood sitting at rest. The bullet is imbedded in the block. Assuming no friction, what is the resultant velocity of the block?

Question

a .08kg bullet travelling at 713m/s strikes a 2.4kg block of wood sitting at rest. The bullet is imbedded in the block. Assuming no friction, what is the resultant velocity of the block?

Answer 1

m₁v₁ + m₂v₂ = (m₁ + m₂)v

0.08*713 + 2.4*0 = (0.08 + 2.4)*v

v = 23 m/s