Let f (x ) = sin(x), on [0,2pi ) find the x-intercepts of f( x).

Question

The x-intercepts are (____________,0) and (____________,0)

Answer 1

sinx = 0

x = pi or 0 radians or 180 degrees or 0 degrees

or the points (0,0) and (pi,0) or (180,0)

sin(pi) = 0

sin(0) = 0

You might be tempted to also include x=2pi but the parenthesis ) means 2pi is excluded.