Raymond B. answered 03/14/21
Math, microeconomics or criminal justice
x^4 -x^3 -7x^2 +x + 6 =
(x-1)(x+1)(x^2-x-1)
-1,1,1/2+(5)^1/2, 1/2-(5)^1/2
x-1=0
x+1=0
x=-1, 1
then solve x^2-x+1 to get x. You get 2 conjugates, 1/2 plus and minus about 2.2
Abraham I.
asked 03/14/21Find all the real zeros of the polynomial
x4-x3-7x2+x+6
real zeros:
Give your answer as a comma-separated list
Raymond B. answered 03/14/21
Math, microeconomics or criminal justice
x^4 -x^3 -7x^2 +x + 6 =
(x-1)(x+1)(x^2-x-1)
-1,1,1/2+(5)^1/2, 1/2-(5)^1/2
x-1=0
x+1=0
x=-1, 1
then solve x^2-x+1 to get x. You get 2 conjugates, 1/2 plus and minus about 2.2
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