
Mark M. answered 03/13/21
Mathematics Teacher - NCLB Highly Qualified
70 000 = a0(2)90/20
70 000 = a0(2)4.5
70 000 = 22.627417 a0
3 093 ≈ a0
A = 3 093(2)240/20
Davie T.
asked 03/12/21The doubling period of a bacterial population is 20 minutes. At time t=90 minutes, the bacterial population was 70000.
a. What was the initial population at time t=0? ___?
b. Find the size of the bacterial population after 4 hours. __?
Mark M. answered 03/13/21
Mathematics Teacher - NCLB Highly Qualified
70 000 = a0(2)90/20
70 000 = a0(2)4.5
70 000 = 22.627417 a0
3 093 ≈ a0
A = 3 093(2)240/20
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