(40x^4y^3)^1/3 = (8*5*x^3*x*y^3) = 2xy(5x)
A = 2xy
B = 5x
Abraham I.
asked 03/10/213√40X4Y3=A3√B
A=
B=
(40x^4y^3)^1/3 = (8*5*x^3*x*y^3) = 2xy(5x)
A = 2xy
B = 5x
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