Let N=number of nickels D= number of dimes Q= number of quarters
From the first sentence: 5N + 10D + 25Q = 340
From the second sentence: D = 2Q
From the third sentence: N + D + Q = 32
Add the first equation and the second equation to lose N:
5N + 10D + 25Q =340
N + D + Q =32
Multiply the second equation by -5
5N + 10 D + 25Q = 340
-5N -5D -5Q = -160
5D +20Q = 180
Since D = 2Q, substitute 2Q for D so 5(2Q) + 20Q = 180
10Q + 20Q = 180
30Q= 180
so Q = 6
If D = 2Q then D =2(6) or 12
If N + D + Q =32, substitute 12 for D and 6 for Q
N + 12 + 6 =32
N +18 = 32
N = 14
Denny Rose
Galion, OH