find the value of six trigonometric functions that correspond to said angle. (-3^(1/2), 1)

Question

if the point is not in the unit circle, do i even need to find the six trigonometric functions?

Answer 1

It's in quadrant II or III, the reference angle is 30 degrees or pi/6. It's a 1, -sqr3, 2 right triangle

in quadrant II, the angle = 150 degrees or 5pi/6 radians

tanx = -1/sqr3

cotx = -sqr3

sinx = 1/2

cosx = -sqr3/2

cscx = 2

secx =-2/sqr3

in quadrant III, the angle x = 210 degrees or 7pi/6 radians

same numerical values for the trig functions in quadrant III, except

tanx and cotx are positive, and sinx and cscx are negative