Stanton D. answered 02/28/21
Tutor to Pique Your Sciences Interest
Hi Again Madison S.,
So there are 2 possible paths to get to the answer here. The faster one (perhaps "cut to the chase" applies?) is to note the change in kinetic energy of the car, and divide by the time interval.
Or you could be nosy, and figure the acceleration:: (Vf-vi)/Δt
and maybe also the distance over which the acceleration took place: vf^2=vi^2+2ad , Either way, the same result.
Look like about (1/4)g, that's conservative driving (thumbs up!).
Now here's a thought for you. Obviously you notice a change in position visually!
The first derivative of position with respect to time, velocity, you can see that visually but not detect otherwise, right? (OK, maybe you could hear engine noise)
The second derivative of position with respect to time, acceleration, that is a steady push back into your car seat. You can always detect that starting, though your body would eventually adapt and disregard it.
Now, what about 3rd, 4th, etc derivatives? How would you verbally characterize them, and what effect would they have on your body in the car seat?
--Cheers, --Mr. d.