
Patrick B. answered 02/26/21
Math and computer tutor/teacher
First it is improper top-heavy so you divide the polynomials..
(1/2)x+4
__________________
2x - 4 | x^2 + 6x - 10
x^2 - 2x
---------------
8x - 10
8x - 16
-----------
6
So y = (1/2)x+4 + 6/(2x-4)
= (1/2)x +4 + 3/(x-2)
= (1/x)x+4 + e, where 3/(x-2) is an error term
The graph is a line, plus or minus, give or take,
the error term value 3/(x-2)
So with the exception of the asymptote at x=2, the domain
and the range is all reals