
Anthony T. answered 02/23/21
Patient Science Tutor
The intensity of sound in decibels is defined as 10 log(I/Io) where I/Io is the ratio of the sound's power in watts/m2 to the intensity of the human threshold of hearing.
To determine the relative loudness of a 50 decibel sound to 40 decibel sound, calculate the I/Io for each decibel level and divide the results.
So for 50 db, I/Io = 100000 and for 40 db I/Io = 10000. The ratio is 10, so the correct answer is that 50 db sound is 10 times as loud as the 40 db sound.