Raymond B. answered 02/23/21
Math, microeconomics or criminal justice
Let C = commercial speed, J= jet speed, J=2C
Let T = jet time, 140+T = commercial time
distance = rate of speed times time
JT = (140+T)C
2CT = 140C + CT
CT =140C
T = 140
140+T = 280 = time for the commercial plane = 280 minutes between Vancouver to Regina = 280/60 = 28/6 = 4 2/3 hours = 4 hours and 40 minutes