Another bowling ball is suspended from the ceiling on a rope. You decide to start it swinging by pulling back on it so that it is raised 1.3 meters higher than it was to start You let It swing.

Question

How fast it it moving at the bottom of its swing?

Answer 1

If the rope is considered to be massless, then the ball moves from one height to a lower height as if it were dropped that distance.

From the energy equation, you know that when a ball is dropped, the velocity (v) is

v = sqrt(2gh) where g = the gravitational constant (9.8 m/s) and h is the height (m) dropped.

In our case v = sqrt(2*9.8*1.3) = sqrt(25.48) = 5.05 m/sec