Hi Giselle V.,
You have the equations correct. With v = √(Gme/r) and T = 2πr/v you should get T = 2π√(r3/Gme).
T = 2π√{[6*6.38x106]3/[(6.67x10-11)(5.98x1024)]} = 74511.66 seconds or 20.70 hours.
I hope this helps, Joe.
Giselle V.
asked 02/20/21A satellite circles the earth in an orbit whose radius is six times the earth's radius. The earth's mass is 5.98 1024 kg, and its radius is 6.38
106 m. What is the period of the satellite?
I used the formulas v = Sqrt GM/ r and then t=2pi r /v and I got 5067.85
Hi Giselle V.,
You have the equations correct. With v = √(Gme/r) and T = 2πr/v you should get T = 2π√(r3/Gme).
T = 2π√{[6*6.38x106]3/[(6.67x10-11)(5.98x1024)]} = 74511.66 seconds or 20.70 hours.
I hope this helps, Joe.
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