2x²+2x+3y=0 precalculus

Answer 1

2x² + 2x + 3y = 0

3y = -2(x² - x)

3y = -2(x² - x + 1/4 - 1/4)

3y = -2(x - 1/2)² + 1/2

y = (-2/3)(x - 1/2)² + 1/6

This is a parabola opening downward with vertex (maximum point) (1/2, 1/6)