How much work would be required to move a 0.682 kg object from a height of 2.41 m to a height of 3.63 m? The object is stationary at both heights.

Question

How much work would be required to move a 0.682 kg object from a height of 2.41 m to

          a height of 3.63 m? The object is stationary at both heights.

      4. Calculate the total mechanical energy of a 45.3 kg object that is moving with a speed of

           22.2 m/s at a height of 0.388 m above Earth’s surfa

Answer 1

(A) Work = Force x distance = change in potential energy = 0.682 x 9.8 x (3.63 - 2.41)

KE = 0.5 x 45.3 x 22.2² J

PE = 45.3 x 9.8 x 0.388

Mechanical energy = KE + PE