Raymond B. answered 02/17/21
Math, microeconomics or criminal justice
tan33 = .65 = h/(300+x)
tan52 = 1.28 = h/x
(300+x).65 = h = 1.28x
1.28X- .65x = .63x =195
x = 309.5
h = tan52(309.5 = 396.2 feet
Madina A.
asked 02/17/21To estimate the height of a building, two students find the angle of elevation from a point (at ground level) down the street from the building to the top of the building is 33∘. From a point that is 300 feet closer to the building, the angle of elevation (at ground level) to the top of the building is 52∘. If we assume that the street is level, use this information to estimate the height of the building.
Raymond B. answered 02/17/21
Math, microeconomics or criminal justice
tan33 = .65 = h/(300+x)
tan52 = 1.28 = h/x
(300+x).65 = h = 1.28x
1.28X- .65x = .63x =195
x = 309.5
h = tan52(309.5 = 396.2 feet
Let h= height
tan 33 = h/(33+X) = 0.649
tan 53 = h/X = 1.327
X = h/1.327
h/ (33+ h/1.327) = 0.649
h*1.327 = 0.649( 33+h) = 21.417 +0.649 h
gives h= 21.417/0.678
h= 31.59 ft
Dr Gulshan S.
02/17/21
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Stephanie C.
how did you get the .63x?02/18/22