While playing a game of "catch" on the quadrangle, you throw a ball at an initial velocity of 18.9 m/s (approximately 42.3 mi/hr), at an angle of 41.3 degrees above horizontal. The ball flies past your friend, and lands on the ground. You let the ball go at a height of 1.58 m above the ground. Define upward as the positive y direction, and the horizontal direction of the ball's travel as the positive x direction. You can assume that air resistance and any effects of the ball spinning are so small that they can be ignored; this means that gravity is the only force causing an acceleration.
1. What is the y-component of velocity, just before the ball hits the ground? Hints: look at the y dimension; split the initial velocity into components; you can assume the height is the same as the ground; the velocity will not be zero; it may help to ask yourself if this velocity should be positive or negative; remember that taking the square root introduces a "plus or minus".
? m/s
2. For how much time is the ball in the air?
? s
3. How far horizontally does the ball travel before it hits the ground?
? m
4. What is the magnitude of the velocity of the ball, just before it hits the ground? Hints: remember that velocity is a vector, with x and y components. Ask yourself what the x-component of acceleration is.
? m/s
5. What is the angle of the total velocity of the ball, just before it hits the ground? Hint: notice the way in which the angle is defined in the answer below.
? degrees clockwise from (below) the positive x axis.