
Michael M. answered 02/16/21
Math, Chem, Physics, Tutoring with Michael ("800" SAT math)
The only time it's undefined is when the denominator equals 0.
Rewrite tan x as sin x/ cos x.
Therefore the function becomes: sin x / (cos x (1 - 2cos2x))
Therefore cos x(1-2cos2x )≠ 0
We'll solve for x.
Therefore we got 2 cases:
Case 1: cos x ≠ 0
cos x = 0 when x = π/2 + πn
Therefore it's undefined whenever x = π/2 + πn
Case 2: 1-2cos2x ≠ 0
1 ≠ 2cos2x
1/2 ≠cos2x
√2/2 ≠ cos x
cos x = √2/2 when x = π/4 + 2πn and x = -π/4 + 2πn.
Therefore it's also undefined whenever x = π/4 + 2πn and x = -π/4 + 2πn.