
William W. answered 02/13/21
Experienced Tutor and Retired Engineer
One of the kinematic equations of motion is
where "vf" is the final velocity, "vi" is the initial velocity, "a" is the acceleration which in this case is the acceleration due to gravity also known as "g" which is -9.8 m/s2, "xf" is the final height and "xi" is the initial height. We can let vi = 0 (dropping means it initially was not moving). We can also let xf = 0 because we want to know the height from the ground up so we can think about the ground as zero height.
So, with the zeros plugged in, the equation becomes vf2 = -2axi or xi = -vf2/(2a)
Plugging in the numbers, we get:
xi = -vf2/(2a)
xi = -(11)2/(2(-9.8))
xi = - 121/(-19.6) = 6.2 m