
Yefim S. answered 02/10/21
Math Tutor with Experience
By rational zeros theorem possible zeros: ±1, ±3.
We check 3 using synthetic division:
3 I 1 -5 5 3
3 -6 -3
1 -2 -1 0
We set 0 quotient: x2 - 2x - 1 = 0; x = 1 ± √2
So, solution set of this equation: {1 - √2, 1 + √2, 3}