Richard P. answered 02/02/21
PhD in Physics with 10+ years tutoring experience in STEM subjects
Assuming that 4 b means σ = 4 x 10^-24 cm^2, and the flux rate is R = 1012 /cm^2 s),
for a given nucleus, one would have to wait t = 1/(R σ) = 1/( 1012 x 4 x 10^-24) = 2.5 x 10 20 s - a very long time.
However for the target over all, this number would be divided by the product of the beam area and the areal density of nuclei,