When a 0.622 kg basketball hits the floor, its velocity changes from 4.23 m/s down to 3.85 m/s up. What impulse was given to the ball?

Answer 1

When a 0.622 kg basketball hits the floor, its velocity changes from 4.23 m/s down to 3.85 m/s up. What impulse was given to the ball?

Impulse = Change in momentum

= Mass * Change in Velocity = 0.622 (4.23 - 3.85) = 0.23636 Kgm/s