
Bradford T. answered 01/31/21
Retired Engineer / Upper level math instructor
pH = -log[H30+] = -log(4.1x10-4) = -(log(4.1) + log(10-4)) = -(06.12 - 4) = 3.4
Jessica R.
asked 01/31/21Simplify your answer. Type an integer or decimal rounded to the nearest tenth as needed.
Bradford T. answered 01/31/21
Retired Engineer / Upper level math instructor
pH = -log[H30+] = -log(4.1x10-4) = -(log(4.1) + log(10-4)) = -(06.12 - 4) = 3.4
David C. answered 01/31/21
Enthusiastic, patient, and effective tutor.
This question can be made easier than you think just by recalling the definition of pH
With this in mind, you can use your calculator's log button to find the pH directly from the given hydronium concentration.
Good Luck,
Let me know if this helped or if you need clarification.
David
David C.
Maybe it was meant as an application of logs? Maybe something like Let X = -log(4.1x10^-4) and then solve for X by using your calculator. That’s my guess about why it’s a PreCalculus problem.01/31/21
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Jessica R.
Hi, thank you so much for your help! But, I'm still confused on how to make this into a math problem as this problem was in my Pre-calculus homework01/31/21