G(t) = 396 * (12.375/396)^(t/225) = 396 * (1/32)^(t/225) = 396 * (2^-5)^(t/225) = 396 * 2^(-5t/225) =
396 * 2^(-t/45)
The half-life is 45 minutes.
After 53 minutes, the amount of goo is 396 * 2^(-53/45) = 396 * 2^-2*2^(37/45) = 99 *237/45 = 175.0446
Madina A.
asked 01/30/21At the beginning of an experiment, a scientist has 396 grams of radioactive goo. After 225 minutes, her sample has decayed to 12.375 grams.
What is the half-life of the goo in minutes? $5
Find a formula for G(t), the amount of goo remaining at time t G(t)=rect
How many grams of goo will remain after 53 minutes?
G(t) = 396 * (12.375/396)^(t/225) = 396 * (1/32)^(t/225) = 396 * (2^-5)^(t/225) = 396 * 2^(-5t/225) =
396 * 2^(-t/45)
The half-life is 45 minutes.
After 53 minutes, the amount of goo is 396 * 2^(-53/45) = 396 * 2^-2*2^(37/45) = 99 *237/45 = 175.0446
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