Talia N. answered 01/30/21
Astronomy graduate with expertise in mathematics and physical sciences
Hi Jenson,
Since I don't know what the previous problem was, let's just call the electrical force they previously felt as F1 and their distance r.
According to Coloumb's Law: Fe = k q1q2 / r2
What stays the same regardless of how far away these two people are from one another? k is Coloumb's constant and, unless something weird is happening, the charges of the two people will remain the same.
So if F1 = k q1q2 / r2, how can we represent the force when they are a factor of 10 further away? Well that's the same as saying F2 = k q1q2 / (r/10)2. When we relate F1 and F2 we can see that the force is reduced by a factor of 100. That is, F1 = 100*F2
I hope that helps! Let me know if you have any other questions.