Inactive Tutor answered 01/27/21
Let x = length and y = width
Area = xy = 60
x=2y+2
xy = (2y+2)y = 2y2+2y = 60
2y2+2y-60 = 0 --> y2+y-30 =0
(y+6)(y-5) = 0 --> y = -6, 5 Choose the positive one since it is a measurement
x = 2y+2 = 10+2 = 12
Sarai S.
asked 01/27/21The length of a rectangle is 2 more than twice the width. The area of the rectangle is 60. Find the dimensions of the rectangle. What is the length of the rectangle?
Inactive Tutor answered 01/27/21
Let x = length and y = width
Area = xy = 60
x=2y+2
xy = (2y+2)y = 2y2+2y = 60
2y2+2y-60 = 0 --> y2+y-30 =0
(y+6)(y-5) = 0 --> y = -6, 5 Choose the positive one since it is a measurement
x = 2y+2 = 10+2 = 12
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