What is the magnitude of the average acceleration of a skier who, starting from rest, reaches a speed of 5.8 m/s when going down a slope for 3.5 s?

Question

I understand how to get the average acceleration which I got 1.66. How do I know how far the skier travels at this time?

Answer 1

An easy way is to consider the skier's average speed as (5.8 + 0)/2 = 2.9 and then traveling at an average of 2.9 m/s for 3.5 s gives 2.9•3.5 = 10.15 meters

Another way is to use the acceleration you calculated (should have been a = 1.65714 m/s²) and use the kinematics equation x = v_it + 1/2at²

x = (0)(3.5) + 1/2(1.65714)(3.5²) = 10.15 meters as well

Of course you should report your answer with 2 significant figures.