Integrate the following

Question

Integrate the following:

∫ sec(3z+4)dz

Answer 1

integral of secant is the integral of 1/cosine

let u= cosx then du/dx = sinx

then integral of 1/u du = sinx/cosx = (ln(absolute value of u) + c

that's maybe a start? at least a step in a logical direction. but someone will come up with a more definite solution. Problem of the Day, better than Number 46 replacing 45, in the number of things, so to speak

Answer 2

^{Use a u substitution for 3z+4=u. So du=3dz}

This becomes 1/3∫secudu=1/3ln|secu+tanu|+c=1/3ln|sec(3z+4)+tan(3z+4)|+c