Quadratic Function

Question

A farmer with 1200 m of fencing wants to enclose a rectangular area and then divide it into four pens with fencing parallel to one side of the rectangle. What is the largest possible total area of the four pens?

Answer 1

5W + 2L = 1200

2L = 1200-5W

L = 600 -5W/2

Area = LW = (600-5W/2)W = 600W -(5/2)W^2

A'(W) = 600-5W =0

5W =600

W = 600/5 = 120 m

L = 600-300= 300 m

max Area = 120(300) = 36,000 square meters