Daniel B. answered 01/19/21
A retired computer professional to teach math, physics
You are correct.
You can manipulate dimensions just like numbers:
A = BC
Therefore
B = A/C = (L/M) / (L/T) = T/M
Elle B.
asked 01/19/21Then B must have the dimensions:
A. M/L2T
B. T/M
C. L2T/M
D. L2/TM
E. TM/L2
I tried to approach this problem as: a= bc therefore (length/mass) = (?/?)(length/time)
i figured that the answer could possibly be B. time/mass because time would cancel out but i am not sure if i am on the right track
Daniel B. answered 01/19/21
A retired computer professional to teach math, physics
You are correct.
You can manipulate dimensions just like numbers:
A = BC
Therefore
B = A/C = (L/M) / (L/T) = T/M
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