Use the properties of logarithms to write the expression as a single logarithm, if possible. 6logc3x^4−1/4logc(3x+7)

Answer 1

I assume these are logs to the base c

6log_c(3x⁴) - (1/4)log_c(3x+7)

= log_c(3⁶x²⁴) - log_c((3x+7)^1/4) --> alog(b) = log(b^a)

= log_c((729x²⁴)/(3x+7)^1/4) --> 3⁶=729 and log(a)-log(b) = log(a/b)